1. F × H : 21 × 19 : : M × O : ?
(a) 13 × 15
(b) 14 × 12
(c) 20 × 19
(d) 21 × 23
2. NPRT : MNOP : : ? : EFGH
(a) FHJL
(b) FHIK
(c) FHKM
(d) FGKL
3. 4 : 8 : : 1 : ?
(a) 9
(b) 3
(c) 1
(d) 0
4. 10 : 14 : : 7 : ?
(a) 9
(b) 13
(c) 15
(d) 17
5. LIME : 20 : : LEMON : ?
(a) 60
(b) 30
(c) 40
(d) 50
Direction (6 - 7): Which one set of letters when sequentially placed at the gaps will complete the given letter series?
6. ab_accab_acc_bba_cabba_c
(a) bbacc
(b) acbcc
(c) bcabb
(d) bcbba
7. aa_abba_babbaa_ab_
(a) babb
(b) baba
(c) aaba
(d) abaa
8. If FUTURE is coded as UFTUER then how will NATURE be coded ?
(a) ANUTER
(b) ANTURE
(c) ANTUER
(d) ANUTRE
9. If TEA is coded as 100, then how will you code FAT?
(a) 120
(b) 150
(c) 140
(d) 130
10. If A represents ‘×’, B represents ‘÷’, C represents ‘+’ and D represents ‘-‘’, then find the value of 2 A 8 D 5 C 9 B 3?
(a) 11
(b) 13
(c) 15
(d) 14
Answers:
1: (b)
21 and 19 represents the number of letters that come after F and H in alphabetical sequence.
2: (a)
In the group MNOP, the letters are shifted +1, +2, +3, +4 places in alphabetical sequence to get NPRT. Similarly, EFGH can be converted to FHJL
3: (c)
4 and 8 are 22 and 23 respectively. So, 12 and 13 are the next numbers in the group.
4: (a)
10/2 + 2 = 7
Therefore, 14/2 + 2 = 9
5: (b)
The sum of alphabetical positions of L, I, M and E is 12+9+13+5=39. So, 39+1=40/2=20.
The sum of alphabetical positions of L, E, M, O and N is 12+5+13+15+14=59. So, 59+1=60/2=30.
6: (a)
The pattern here will be ‘abbaccabbacc’
7: (a)
The pattern here will be ‘aababb’.
8: (c)
In FUTURE, first two letters are reversed, last two letters are reversed and middle two letters are unchanged. So, NATURE will be coded as ANTUER.
9: (a)
In TEA, the alphabetical positions of T, E and A are 20, 5 and 1. The positions numbers are multiplied to get the code as 100. Similarly, FAT can be coded as 120.
10: (d)
2 A 8 D 5 C 9 B 3 = 2 × 8 - 5 + 9 ÷ 3 = 16 – 5 + 3 = 14
1. F × H : 21 × 19 : : M × O : ?
(a) 13 × 15
(b) 14 × 12
(c) 20 × 19
(d) 21 × 23
2. NPRT : MNOP : : ? : EFGH
(a) FHJL
(b) FHIK
(c) FHKM
(d) FGKL
3. 4 : 8 : : 1 : ?
(a) 9
(b) 3
(c) 1
(d) 0
4. 10 : 14 : : 7 : ?
(a) 9
(b) 13
(c) 15
(d) 17
5. LIME : 20 : : LEMON : ?
(a) 60
(b) 30
(c) 40
(d) 50
Direction (6 - 7): Which one set of letters when sequentially placed at the gaps will complete the given letter series?
6. ab_accab_acc_bba_cabba_c
(a) bbacc
(b) acbcc
(c) bcabb
(d) bcbba
7. aa_abba_babbaa_ab_
(a) babb
(b) baba
(c) aaba
(d) abaa
8. If FUTURE is coded as UFTUER then how will NATURE be coded ?
(a) ANUTER
(b) ANTURE
(c) ANTUER
(d) ANUTRE
9. If TEA is coded as 100, then how will you code FAT?
(a) 120
(b) 150
(c) 140
(d) 130
10. If A represents ‘×’, B represents ‘÷’, C represents ‘+’ and D represents ‘-‘’, then find the value of 2 A 8 D 5 C 9 B 3?
(a) 11
(b) 13
(c) 15
(d) 14
Answers:
1: (b)
21 and 19 represents the number of letters that come after F and H in alphabetical sequence.
2: (a)
In the group MNOP, the letters are shifted +1, +2, +3, +4 places in alphabetical sequence to get NPRT. Similarly, EFGH can be converted to FHJL
3: (c)
4 and 8 are 22 and 23 respectively. So, 12 and 13 are the next numbers in the group.
4: (a)
10/2 + 2 = 7
Therefore, 14/2 + 2 = 9
5: (b)
The sum of alphabetical positions of L, I, M and E is 12+9+13+5=39. So, 39+1=40/2=20.
The sum of alphabetical positions of L, E, M, O and N is 12+5+13+15+14=59. So, 59+1=60/2=30.
6: (a)
The pattern here will be ‘abbaccabbacc’
7: (a)
The pattern here will be ‘aababb’.
8: (c)
In FUTURE, first two letters are reversed, last two letters are reversed and middle two letters are unchanged. So, NATURE will be coded as ANTUER.
9: (a)
In TEA, the alphabetical positions of T, E and A are 20, 5 and 1. The positions numbers are multiplied to get the code as 100. Similarly, FAT can be coded as 120.
10: (d)
2 A 8 D 5 C 9 B 3 = 2 × 8 - 5 + 9 ÷ 3 = 16 – 5 + 3 = 14
