In Quantitative Aptitude section for IBPS Clerk 2016- Data Interpretation, simplification,series, mixed type questions play important role in preliminary exam
In each of the following questions, two equations are given. You have to solve them and give answer
1).Ⅰ. 4x + 7y = 42 Ⅱ. 3x – 11y = -1
a) x > y
b) x ≥ y
c) x < y
d) x ≤ y
e) x = y or relationship cannot be established
2). Ⅰ. x2 + 14x + 49 = 0 Ⅱ. y2 + 9y = 0
a) x > y
b) x ≥ y
c) x < y
d) x ≤ y
e) x = y or relationship cannot be established
3). Ⅰ. 3×2 – 4x – 32 = 0 Ⅱ. 2y2 + 5y – 3 = 0
a) x > y
b) x ≥ y
c) x < y
d) x ≤ y
e) x = y or relationship cannot be established
4). Ⅰ. 9×2 – 29x + 22 = 0 Ⅱ. 7y2 – 7y – 12 = 0
a) x > y
b) x ≥ y
c) x < y
d) x ≤ y
e) x = y or relationship cannot be established
5). Ⅰ. x2 + 14x + 49 = 0 Ⅱ. 2y2 – 17y + 36 = 0
a) x > y
b) x ≥ y
c) x < y
d) x ≤ y
e) x = y or relationship cannot be established
What should come in the place of question mark (?) in the following questions?
6). 3√13824 + √1849 = 3√9261 + √?
a) 1256
b) 1936
c) 2116
d) 2456
e) 2216
7). (0.8) / (0.2)2 × (0.6)2 = (2.4)2 × ?
a) 1.8
b) 1.4
c) 1.25
d) 1.6
e) 2.6
8). 7654.32 + 8962.81 + 3432.12 – 512.32 + 212.82 + 316.84 = ?
a) 20056.49
b) 20046.79
c) 20065.49
d) 20066.59
e) 20062.59
9). 812 + 912 + 516 + 241 + 346 + 329 = 12 × ?
a) 263
b) 265
c) 326
d) 363
e) 236
10).4√1296 + 4√2401 + 4√6561 – 4√256 = ?
a) 14
b) 18
c) 22
d) 16
e) 15
Answers
1).a From Eq Ⅰ and Ⅱ
y = 2
x = 7
x > y
2).e Ⅰ. x2 + 7x + 7x + 49 = 0
x (x + 7) + 7 (x + 7) = 0
x = -7, -7
Ⅱ. y ( y + 9) = 0
y = 0, -9
Relation can’t be established
3).e Ⅰ. 3×2 – 12x + 8x – 32 = 0
3x (x – 4) + 8 (x – 4) = 0
x =4, – (8 / 3)
Ⅱ. 2y2 +6y – y – 3 = 0
2y (y + 3) – 1 (y + 3) = 0
y = -3, (1 / 2)
Relation can’t be established
4).b Ⅰ. 9×2 – 18 – 11x + 22 = 0
9x (x – 2) – 11 (x – 2) = 0
x =2, (11 / 9)
Ⅱ. 7y2 – 14y + 6y – 12 = 0
7y (y – 2) + 6 (y – 2) = 0
y = 2, – (6 / 7)
x ≥ y
5).c Ⅰ. x2 + 7x + 7x + 49 = 0
x (x + y) + 7 ( x + 7) = 0
x = -7
Ⅱ. 2y2 – 8y – 9y + 36 = 0
2y (y – 4) – 9 (y – 4) = 0
y = 4, (9 / 2)
x < y
6). c 3√13824 + √1849 = 3√9261 + √?
Or, 24 + 43 = 21 + √?
Or, √? = 67 – 21 =46
? = 2116
7).c (0.8) ÷ (0.2)2 × (0.6)2 = (2.4)2 × ?
Or, 5.76 × ? = (0.8 / 0.04) × 0.36 = 20 × 0.36 = 7.20
? = (7.20 / 5.76) = 1.25
8).d ? = 7654.32 + 8962.81 + 3432.12 – 512.32 + 212.82 + 316.84
= 20066.59
9)a . 812 + 912 + 516 + 241 + 346 + 329 = 12 × ?
Or, 3156 = 12 × ?
Or, ? = (3156 / 12) = 263
10).b ? = 4√1296 + 4√2401 + 4√6561 – 4√256
Or, ? = 6 + 7 + 9 – 4 = 18
